| |
| Recipe 6.8: Reading an Object from a URI, File, or Stream |
Last Updated: Sep 8, 2003
Status: Draft
|
|
|
|
How important is this problem to you?
(Login to Vote)
5.00 Rating, 2 Votes
|
|
How acceptable is the proposed solution?
(Login to Vote)
0.00 Rating, 0 Votes
|
|
Problem:
You have a file, a stream, or a URI pointing to a serialized, stored object. You want to read the data and instantiate that object.
Solution:
Use from or as:
class MyClass {
from IOStream { ... }
}
my $obj = URI('ftp://serialized.txt') as MyClass;
Discussion:
Transformations exist between the URI, File and IOStream classes. If you want your class to be be instantiated via any one of these other classes, therefore, just put a from IOStream declaration in your class.
Issue:
Having a one-liner for this is very, very cool. One catch: if MyClass has a transformer from string (quite possible), then it would interpret the URI as a string, and not do the longer URI --> IOStream --> MyClass transformation path. That needs a fix.
|
|
